3(x+1)=4[x-(2-x)]

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Solution for 3(x+1)=4[x-(2-x)] equation:


Simplifying
3(x + 1) = 4[x + -1(2 + -1x)]

Reorder the terms:
3(1 + x) = 4[x + -1(2 + -1x)]
(1 * 3 + x * 3) = 4[x + -1(2 + -1x)]
(3 + 3x) = 4[x + -1(2 + -1x)]
3 + 3x = 4[x + (2 * -1 + -1x * -1)]
3 + 3x = 4[x + (-2 + 1x)]

Reorder the terms:
3 + 3x = 4[-2 + x + 1x]

Combine like terms: x + 1x = 2x
3 + 3x = 4[-2 + 2x]
3 + 3x = [-2 * 4 + 2x * 4]
3 + 3x = [-8 + 8x]

Solving
3 + 3x = -8 + 8x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-8x' to each side of the equation.
3 + 3x + -8x = -8 + 8x + -8x

Combine like terms: 3x + -8x = -5x
3 + -5x = -8 + 8x + -8x

Combine like terms: 8x + -8x = 0
3 + -5x = -8 + 0
3 + -5x = -8

Add '-3' to each side of the equation.
3 + -3 + -5x = -8 + -3

Combine like terms: 3 + -3 = 0
0 + -5x = -8 + -3
-5x = -8 + -3

Combine like terms: -8 + -3 = -11
-5x = -11

Divide each side by '-5'.
x = 2.2

Simplifying
x = 2.2

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